05 Mar 15, 04:12AM
(05 Mar 15, 03:27AM)Cemer Wrote: Solve for the equation of the tangent of 3x^2 + 2x -1 that is perpendicular to 3x - y + 6 = 0
Derivative is tangent so 6x+2. I'm guessing that's y? 6x+2=y. y=3x+6. How do you get something with a slope of 6 to be perpendicular with something that needs a slope of 1/3 to be perpendicular? Well... Assume 6x+2=z. Since the z and y planes are technically perpendicular, this should work.
z=6x+2 and y=3x-6
Like so? I'm tired.