16 Apr 11, 12:03AM
V-Man... I'm not sure if this is any more efficient than yours, but...
Could it be that you're already doing this? I can't tell.
[SELECT ALL] Code:
nthroot = [ result (powf 2 (divf (log2 $arg2) $arg1)) ]
Could it be that you're already doing this? I can't tell.