24 May 12, 06:39PM
(This post was last modified: 24 May 12, 06:42PM by Roflcopter.)
(24 May 12, 06:19PM)Sarath Wrote: #1. c=sqr[a^2+b^2].
If. a and b are primes , then square root of a^2 + b^2 will not be an integer. To satisfy the
Pythagoras theorem a, b and c should be integers.
Seems a bit like hand-waving. Why cannot the square root of two primes squared be an integer? It's a correct statement but the proof of it is essentially as hard as the original question.