Music: we use to call it 'dynamic friction', as it's different from 'static friction' (us), but I guess you mean that.
Luc@s, thanks, that's just a nice start, but yes, I'd need some formulas too. The main thing that has been bugging me up is the fact I don't have the angle of the slope, so I figured out that I must do everything in 'reverse'.
So, the energy produced by the spring should be
Espring = 1/2*k*(L-L0)^2
assuming the block must touch the wall, the final length (L) of the spring must be 0, so Espring would be:
Espring = 1/2*2*(-0.01)^2 = 10^-4
Now, the kinetic energy of the block:
Ek = 1/2*m*v^2
And? How do I proceed here? v would be known if I knew the slope part, but I'm apparently stuck in a thing that should be easy as hell.
EDIT: perhaps a nice approach would be thinking of the of the block Ek = -Espring, Ek = 10^4 J, that is the energy needed to compress the spring at the limit. So:
10^4 = 1/2*m*v^2 ---> v^2 = 10^4/2*m = 0.0025
v = sqrt(v^2) = 0.05 m/s = 5 cm/s
According to this, the initial speed after the slope would be 5 cm/s, or 0,05 m/s, which would have sense, but I feel something is still wrong
Luc@s, thanks, that's just a nice start, but yes, I'd need some formulas too. The main thing that has been bugging me up is the fact I don't have the angle of the slope, so I figured out that I must do everything in 'reverse'.
So, the energy produced by the spring should be
Espring = 1/2*k*(L-L0)^2
assuming the block must touch the wall, the final length (L) of the spring must be 0, so Espring would be:
Espring = 1/2*2*(-0.01)^2 = 10^-4
Now, the kinetic energy of the block:
Ek = 1/2*m*v^2
And? How do I proceed here? v would be known if I knew the slope part, but I'm apparently stuck in a thing that should be easy as hell.
EDIT: perhaps a nice approach would be thinking of the of the block Ek = -Espring, Ek = 10^4 J, that is the energy needed to compress the spring at the limit. So:
10^4 = 1/2*m*v^2 ---> v^2 = 10^4/2*m = 0.0025
v = sqrt(v^2) = 0.05 m/s = 5 cm/s
According to this, the initial speed after the slope would be 5 cm/s, or 0,05 m/s, which would have sense, but I feel something is still wrong